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13406473 is a prime number
BaseRepresentation
bin110011001001…
…000100001001
3221020010020001
4303021010021
511413001343
61155203001
7221644633
oct63110411
927203201
1013406473
117627533
1245a6461
132a15232
141acda53
15129c44d
hexcc9109

13406473 has 2 divisors, whose sum is σ = 13406474. Its totient is φ = 13406472.

The previous prime is 13406461. The next prime is 13406483. The reversal of 13406473 is 37460431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11309769 + 2096704 = 3363^2 + 1448^2 .

It is a cyclic number.

It is not a de Polignac number, because 13406473 - 29 = 13405961 is a prime.

It is not a weakly prime, because it can be changed into another prime (13406443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6703236 + 6703237.

It is an arithmetic number, because the mean of its divisors is an integer number (6703237).

Almost surely, 213406473 is an apocalyptic number.

It is an amenable number.

13406473 is a deficient number, since it is larger than the sum of its proper divisors (1).

13406473 is an equidigital number, since it uses as much as digits as its factorization.

13406473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 28.

The square root of 13406473 is about 3661.4850812205. The cubic root of 13406473 is about 237.5590132209.

The spelling of 13406473 in words is "thirteen million, four hundred six thousand, four hundred seventy-three".