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1340649034801 is a prime number
BaseRepresentation
bin10011100000100100111…
…010001101010000110001
311202011110010200101002121
4103200210322031100301
5133431122123103201
62503515145314241
7165600350526046
oct23404472152061
94664403611077
101340649034801
1147762547a72a
121979b0795981
139956578355b
1448c600251cd
1524d178b39a1
hex13824e8d431

1340649034801 has 2 divisors, whose sum is σ = 1340649034802. Its totient is φ = 1340649034800.

The previous prime is 1340649034723. The next prime is 1340649034811. The reversal of 1340649034801 is 1084309460431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1229526145600 + 111122889201 = 1108840^2 + 333351^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340649034801 - 217 = 1340648903729 is a prime.

It is not a weakly prime, because it can be changed into another prime (1340649034811) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670324517400 + 670324517401.

It is an arithmetic number, because the mean of its divisors is an integer number (670324517401).

Almost surely, 21340649034801 is an apocalyptic number.

It is an amenable number.

1340649034801 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340649034801 is an equidigital number, since it uses as much as digits as its factorization.

1340649034801 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 248832, while the sum is 43.

The spelling of 1340649034801 in words is "one trillion, three hundred forty billion, six hundred forty-nine million, thirty-four thousand, eight hundred one".