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13406638523569 is a prime number
BaseRepresentation
bin1100001100010111100111…
…1011010100010010110001
31202110122212200121211121121
43003011321323110102301
53224123243430223234
644302531423222241
72552412000125464
oct303057173242261
952418780554547
1013406638523569
1142a97a5a33105
121606368147981
137633187588c5
14344c55b2b2db
15183b0dc954b4
hexc3179ed44b1

13406638523569 has 2 divisors, whose sum is σ = 13406638523570. Its totient is φ = 13406638523568.

The previous prime is 13406638523543. The next prime is 13406638523617. The reversal of 13406638523569 is 96532583660431.

13406638523569 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13312916823969 + 93721699600 = 3648687^2 + 306140^2 .

It is a cyclic number.

It is not a de Polignac number, because 13406638523569 - 219 = 13406637999281 is a prime.

It is a super-2 number, since 2×134066385235692 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13406638523519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6703319261784 + 6703319261785.

It is an arithmetic number, because the mean of its divisors is an integer number (6703319261785).

Almost surely, 213406638523569 is an apocalyptic number.

It is an amenable number.

13406638523569 is a deficient number, since it is larger than the sum of its proper divisors (1).

13406638523569 is an equidigital number, since it uses as much as digits as its factorization.

13406638523569 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 83980800, while the sum is 61.

The spelling of 13406638523569 in words is "thirteen trillion, four hundred six billion, six hundred thirty-eight million, five hundred twenty-three thousand, five hundred sixty-nine".