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1340663852357 = 7577631769239
BaseRepresentation
bin10011100000100101110…
…010101110110101000101
311202011111011120011221222
4103200211302232311011
5133431134421233412
62503520435050125
7165600620501654
oct23404562566505
94664434504858
101340663852357
11477632880345
121979b5740945
1399568870b3b
1448c61da119b
1524d18d3e072
hex13825caed45

1340663852357 has 4 divisors (see below), whose sum is σ = 1340666379360. Its totient is φ = 1340661325356.

The previous prime is 1340663852293. The next prime is 1340663852371. The reversal of 1340663852357 is 7532583660431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340663852357 - 26 = 1340663852293 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340663852299 and 1340663852308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340663852057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126857 + ... + 1642382.

It is an arithmetic number, because the mean of its divisors is an integer number (335166594840).

Almost surely, 21340663852357 is an apocalyptic number.

It is an amenable number.

1340663852357 is a deficient number, since it is larger than the sum of its proper divisors (2527003).

1340663852357 is an equidigital number, since it uses as much as digits as its factorization.

1340663852357 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2527002.

The product of its (nonzero) digits is 10886400, while the sum is 53.

The spelling of 1340663852357 in words is "one trillion, three hundred forty billion, six hundred sixty-three million, eight hundred fifty-two thousand, three hundred fifty-seven".

Divisors: 1 757763 1769239 1340663852357