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134068080217 is a prime number
BaseRepresentation
bin111110011011100010…
…1001000111001011001
3110211001102202010120111
41330313011020321121
54144032412031332
6141331240124321
712454221610351
oct1746705107131
9424042663514
10134068080217
1151948a32aa5
1221b971666a1
13c847941ca6
1466bb8a1b61
15374a085947
hex1f37148e59

134068080217 has 2 divisors, whose sum is σ = 134068080218. Its totient is φ = 134068080216.

The previous prime is 134068080187. The next prime is 134068080227. The reversal of 134068080217 is 712080860431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131036036121 + 3032044096 = 361989^2 + 55064^2 .

It is an emirp because it is prime and its reverse (712080860431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134068080217 - 27 = 134068080089 is a prime.

It is a super-3 number, since 3×1340680802173 (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 134068080217.

It is not a weakly prime, because it can be changed into another prime (134068080227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67034040108 + 67034040109.

It is an arithmetic number, because the mean of its divisors is an integer number (67034040109).

Almost surely, 2134068080217 is an apocalyptic number.

It is an amenable number.

134068080217 is a deficient number, since it is larger than the sum of its proper divisors (1).

134068080217 is an equidigital number, since it uses as much as digits as its factorization.

134068080217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64512, while the sum is 40.

The spelling of 134068080217 in words is "one hundred thirty-four billion, sixty-eight million, eighty thousand, two hundred seventeen".