Base | Representation |
---|---|
bin | 111110011011100010… |
… | …1001001000000010011 |
3 | 110211001102202011011212 |
4 | 1330313011021000103 |
5 | 4144032412040114 |
6 | 141331240130335 |
7 | 12454221611552 |
oct | 1746705110023 |
9 | 424042664155 |
10 | 134068080659 |
11 | 51948a33367 |
12 | 21b971669ab |
13 | c847942256 |
14 | 66bb8a1d99 |
15 | 374a085b3e |
hex | 1f37149013 |
134068080659 has 2 divisors, whose sum is σ = 134068080660. Its totient is φ = 134068080658.
The previous prime is 134068080599. The next prime is 134068080677. The reversal of 134068080659 is 956080860431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134068080659 is a prime.
It is not a weakly prime, because it can be changed into another prime (134968080659) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67034040329 + 67034040330.
It is an arithmetic number, because the mean of its divisors is an integer number (67034040330).
Almost surely, 2134068080659 is an apocalyptic number.
134068080659 is a deficient number, since it is larger than the sum of its proper divisors (1).
134068080659 is an equidigital number, since it uses as much as digits as its factorization.
134068080659 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1244160, while the sum is 50.
The spelling of 134068080659 in words is "one hundred thirty-four billion, sixty-eight million, eighty thousand, six hundred fifty-nine".
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