Base | Representation |
---|---|
bin | 1111111110111… |
… | …10001010100001 |
3 | 100100021220222222 |
4 | 13333132022201 |
5 | 233311013022 |
6 | 21145440425 |
7 | 3215440163 |
oct | 777361241 |
9 | 310256888 |
10 | 134079137 |
11 | 69758705 |
12 | 38aa0115 |
13 | 21a1638a |
14 | 13b42933 |
15 | bb87242 |
hex | 7fde2a1 |
134079137 has 2 divisors, whose sum is σ = 134079138. Its totient is φ = 134079136.
The previous prime is 134079103. The next prime is 134079149. The reversal of 134079137 is 731970431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130896481 + 3182656 = 11441^2 + 1784^2 .
It is an emirp because it is prime and its reverse (731970431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134079137 - 212 = 134075041 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 134079097 and 134079106.
It is not a weakly prime, because it can be changed into another prime (134079937) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67039568 + 67039569.
It is an arithmetic number, because the mean of its divisors is an integer number (67039569).
Almost surely, 2134079137 is an apocalyptic number.
It is an amenable number.
134079137 is a deficient number, since it is larger than the sum of its proper divisors (1).
134079137 is an equidigital number, since it uses as much as digits as its factorization.
134079137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15876, while the sum is 35.
The square root of 134079137 is about 11579.2545960437. The cubic root of 134079137 is about 511.8237117390.
The spelling of 134079137 in words is "one hundred thirty-four million, seventy-nine thousand, one hundred thirty-seven".
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