Base | Representation |
---|---|
bin | 11000111110010111… |
… | …00110011100101011 |
3 | 1021121102120211112001 |
4 | 30133023212130223 |
5 | 204424424133101 |
6 | 10054244431431 |
7 | 653156300602 |
oct | 143713463453 |
9 | 37542524461 |
10 | 13408036651 |
11 | 576053a429 |
12 | 27223a8577 |
13 | 1358a982c9 |
14 | 912a22a39 |
15 | 5371a1901 |
hex | 31f2e672b |
13408036651 has 2 divisors, whose sum is σ = 13408036652. Its totient is φ = 13408036650.
The previous prime is 13408036643. The next prime is 13408036709. The reversal of 13408036651 is 15663080431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13408036651 - 23 = 13408036643 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13408036651.
It is not a weakly prime, because it can be changed into another prime (13408036601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6704018325 + 6704018326.
It is an arithmetic number, because the mean of its divisors is an integer number (6704018326).
Almost surely, 213408036651 is an apocalyptic number.
13408036651 is a deficient number, since it is larger than the sum of its proper divisors (1).
13408036651 is an equidigital number, since it uses as much as digits as its factorization.
13408036651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 13408036651 in words is "thirteen billion, four hundred eight million, thirty-six thousand, six hundred fifty-one".
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