Base | Representation |
---|---|
bin | 11110011111011011010100… |
… | …011100011111011011111110 |
3 | 122120210221012120102000012211 |
4 | 132133123110130133123332 |
5 | 120034102403441414202 |
6 | 1153113055243051034 |
7 | 40150323420311014 |
oct | 3637332434373376 |
9 | 576727176360184 |
10 | 134101033154302 |
11 | 39801a24233025 |
12 | 13059818810a7a |
13 | 59a9899c38156 |
14 | 251874b85a8b4 |
15 | 107842031d1d7 |
hex | 79f6d471f6fe |
134101033154302 has 4 divisors (see below), whose sum is σ = 201151549731456. Its totient is φ = 67050516577150.
The previous prime is 134101033154267. The next prime is 134101033154359. The reversal of 134101033154302 is 203451330101431.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1341010331543022 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33525258288574 + ... + 33525258288577.
It is an arithmetic number, because the mean of its divisors is an integer number (50287887432864).
Almost surely, 2134101033154302 is an apocalyptic number.
134101033154302 is a deficient number, since it is larger than the sum of its proper divisors (67050516577154).
134101033154302 is an equidigital number, since it uses as much as digits as its factorization.
134101033154302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67050516577153.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 134101033154302 its reverse (203451330101431), we get a palindrome (337552363255733).
The spelling of 134101033154302 in words is "one hundred thirty-four trillion, one hundred one billion, thirty-three million, one hundred fifty-four thousand, three hundred two".
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