Base | Representation |
---|---|
bin | 111110011100100011… |
… | …0101101011001011111 |
3 | 110211010210122210021200 |
4 | 1330321012231121133 |
5 | 4144120110440203 |
6 | 141334452130543 |
7 | 12455113405011 |
oct | 1747106553137 |
9 | 424123583250 |
10 | 134102046303 |
11 | 51966122245 |
12 | 21ba6606a53 |
13 | c8519a5274 |
14 | 66c21c41b1 |
15 | 374d0449a3 |
hex | 1f391ad65f |
134102046303 has 48 divisors (see below), whose sum is σ = 206611392000. Its totient is φ = 83570258304.
The previous prime is 134102046289. The next prime is 134102046307. The reversal of 134102046303 is 303640201431.
134102046303 is a `hidden beast` number, since 1 + 3 + 4 + 1 + 0 + 20 + 4 + 630 + 3 = 666.
It is not a de Polignac number, because 134102046303 - 217 = 134101915231 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134102046307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 36648088 + ... + 36651746.
It is an arithmetic number, because the mean of its divisors is an integer number (4304404000).
Almost surely, 2134102046303 is an apocalyptic number.
134102046303 is a deficient number, since it is larger than the sum of its proper divisors (72509345697).
134102046303 is a wasteful number, since it uses less digits than its factorization.
134102046303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6476 (or 6473 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 134102046303 its reverse (303640201431), we get a palindrome (437742247734).
The spelling of 134102046303 in words is "one hundred thirty-four billion, one hundred two million, forty-six thousand, three hundred three".
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