Base | Representation |
---|---|
bin | 11110011111011101010010… |
… | …001101011101101010110000 |
3 | 122120211010122121201121002120 |
4 | 132133131102031131222300 |
5 | 120034121214121102422 |
6 | 1153114044455314240 |
7 | 40150426621032552 |
oct | 3637352215355260 |
9 | 576733577647076 |
10 | 134103143144112 |
11 | 3980290727465a |
12 | 1305a10737b980 |
13 | 59a9b4511302c |
14 | 25188abb874d2 |
15 | 10784e56aa45c |
hex | 79f75235dab0 |
134103143144112 has 40 divisors (see below), whose sum is σ = 349670812510656. Its totient is φ = 44283280911936.
The previous prime is 134103143144027. The next prime is 134103143144149. The reversal of 134103143144112 is 211441341301431.
It is a super-2 number, since 2×1341031431441122 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13055207398 + ... + 13055217669.
Almost surely, 2134103143144112 is an apocalyptic number.
134103143144112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
134103143144112 is an abundant number, since it is smaller than the sum of its proper divisors (215567669366544).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134103143144112 is a wasteful number, since it uses less digits than its factorization.
134103143144112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26110425185 (or 26110425179 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 33.
Adding to 134103143144112 its reverse (211441341301431), we get a palindrome (345544484445543).
The spelling of 134103143144112 in words is "one hundred thirty-four trillion, one hundred three billion, one hundred forty-three million, one hundred forty-four thousand, one hundred twelve".
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