Base | Representation |
---|---|
bin | 1100001100100101101110… |
… | …0111101100011101100111 |
3 | 1202111000122120121022122011 |
4 | 3003021123213230131213 |
5 | 3224204022301434003 |
6 | 44304355245215051 |
7 | 2552604555656344 |
oct | 303113347543547 |
9 | 52430576538564 |
10 | 13410425030503 |
11 | 4300369358886 |
12 | 1607044261487 |
13 | 7637a007a557 |
14 | 3450d49897cb |
15 | 183c813e846d |
hex | c325b9ec767 |
13410425030503 has 8 divisors (see below), whose sum is σ = 13561178898240. Its totient is φ = 13259672828160.
The previous prime is 13410425030479. The next prime is 13410425030603. The reversal of 13410425030503 is 30503052401431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13410425030503 - 213 = 13410425022311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13410425030603) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23379151 + ... + 23945887.
It is an arithmetic number, because the mean of its divisors is an integer number (1695147362280).
Almost surely, 213410425030503 is an apocalyptic number.
13410425030503 is a deficient number, since it is larger than the sum of its proper divisors (150753867737).
13410425030503 is an equidigital number, since it uses as much as digits as its factorization.
13410425030503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 832697.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 13410425030503 its reverse (30503052401431), we get a palindrome (43913477431934).
The spelling of 13410425030503 in words is "thirteen trillion, four hundred ten billion, four hundred twenty-five million, thirty thousand, five hundred three".
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