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13410425030503 = 89265871566737
BaseRepresentation
bin1100001100100101101110…
…0111101100011101100111
31202111000122120121022122011
43003021123213230131213
53224204022301434003
644304355245215051
72552604555656344
oct303113347543547
952430576538564
1013410425030503
114300369358886
121607044261487
137637a007a557
143450d49897cb
15183c813e846d
hexc325b9ec767

13410425030503 has 8 divisors (see below), whose sum is σ = 13561178898240. Its totient is φ = 13259672828160.

The previous prime is 13410425030479. The next prime is 13410425030603. The reversal of 13410425030503 is 30503052401431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13410425030503 - 213 = 13410425022311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13410425030603) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23379151 + ... + 23945887.

It is an arithmetic number, because the mean of its divisors is an integer number (1695147362280).

Almost surely, 213410425030503 is an apocalyptic number.

13410425030503 is a deficient number, since it is larger than the sum of its proper divisors (150753867737).

13410425030503 is an equidigital number, since it uses as much as digits as its factorization.

13410425030503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 832697.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 13410425030503 its reverse (30503052401431), we get a palindrome (43913477431934).

The spelling of 13410425030503 in words is "thirteen trillion, four hundred ten billion, four hundred twenty-five million, thirty thousand, five hundred three".

Divisors: 1 89 265871 566737 23662519 50439593 150678932927 13410425030503