Base | Representation |
---|---|
bin | 1100001100100101101110… |
… | …0111101100011111001011 |
3 | 1202111000122120121022202212 |
4 | 3003021123213230133023 |
5 | 3224204022301434403 |
6 | 44304355245215335 |
7 | 2552604555656546 |
oct | 303113347543713 |
9 | 52430576538685 |
10 | 13410425030603 |
11 | 4300369358967 |
12 | 160704426154b |
13 | 7637a007a603 |
14 | 3450d498985d |
15 | 183c813e84d8 |
hex | c325b9ec7cb |
13410425030603 has 2 divisors, whose sum is σ = 13410425030604. Its totient is φ = 13410425030602.
The previous prime is 13410425030479. The next prime is 13410425030659. The reversal of 13410425030603 is 30603052401431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13410425030603 - 28 = 13410425030347 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13410425030603.
It is not a weakly prime, because it can be changed into another prime (13410425230603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705212515301 + 6705212515302.
It is an arithmetic number, because the mean of its divisors is an integer number (6705212515302).
Almost surely, 213410425030603 is an apocalyptic number.
13410425030603 is a deficient number, since it is larger than the sum of its proper divisors (1).
13410425030603 is an equidigital number, since it uses as much as digits as its factorization.
13410425030603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 32.
The spelling of 13410425030603 in words is "thirteen trillion, four hundred ten billion, four hundred twenty-five million, thirty thousand, six hundred three".
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