Base | Representation |
---|---|
bin | 11110011111011110010111… |
… | …001010101000100100100011 |
3 | 122120211020122020121111112001 |
4 | 132133132113022220210203 |
5 | 120034131101301431433 |
6 | 1153114355343344431 |
7 | 40150500366303454 |
oct | 3637362712504443 |
9 | 576736566544461 |
10 | 134104300030243 |
11 | 398033503032a4 |
12 | 1305a38a8b2117 |
13 | 59a9c9a9c053a |
14 | 251897b69312b |
15 | 107856202b57d |
hex | 79f7972a8923 |
134104300030243 has 2 divisors, whose sum is σ = 134104300030244. Its totient is φ = 134104300030242.
The previous prime is 134104300030229. The next prime is 134104300030273. The reversal of 134104300030243 is 342030003401431.
It is a weak prime.
It is an emirp because it is prime and its reverse (342030003401431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134104300030243 is a prime.
It is not a weakly prime, because it can be changed into another prime (134104300030273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67052150015121 + 67052150015122.
It is an arithmetic number, because the mean of its divisors is an integer number (67052150015122).
Almost surely, 2134104300030243 is an apocalyptic number.
134104300030243 is a deficient number, since it is larger than the sum of its proper divisors (1).
134104300030243 is an equidigital number, since it uses as much as digits as its factorization.
134104300030243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 134104300030243 its reverse (342030003401431), we get a palindrome (476134303431674).
The spelling of 134104300030243 in words is "one hundred thirty-four trillion, one hundred four billion, three hundred million, thirty thousand, two hundred forty-three".
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