13410531404201 has 2 divisors, whose sum is σ = 13410531404202. Its totient is φ = 13410531404200.

The previous prime is 13410531404189. The next prime is 13410531404261. The reversal of 13410531404201 is 10240413501431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12636773670976 + 773757733225 = 3554824^2 + 879635^2 .

It is a cyclic number.

It is not a de Polignac number, because 13410531404201 - 2³⁸ = 13135653497257 is a prime.

It is a super-2 number, since 2×13410531404201² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13410531404261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705265702100 + 6705265702101.

It is an arithmetic number, because the mean of its divisors is an integer number (6705265702101).

Almost surely, 2^{13410531404201} is an apocalyptic number.

It is an amenable number.

13410531404201 is a deficient number, since it is larger than the sum of its proper divisors (1).

13410531404201 is an equidigital number, since it uses as much as digits as its factorization.

13410531404201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 13410531404201 its reverse (10240413501431), we get a palindrome (23650944905632).

The spelling of 13410531404201 in words is "thirteen trillion, four hundred ten billion, five hundred thirty-one million, four hundred four thousand, two hundred one".