Base | Representation |
---|---|
bin | 111110011100110011… |
… | …0101000000011001011 |
3 | 110211011101101212020110 |
4 | 1330321212220003023 |
5 | 4144124231204003 |
6 | 141335351325403 |
7 | 12455244462510 |
oct | 1747146500313 |
9 | 424141355213 |
10 | 134110413003 |
11 | 5196a917276 |
12 | 21ba9380863 |
13 | c853644588 |
14 | 66c3361307 |
15 | 374db48a03 |
hex | 1f399a80cb |
134110413003 has 64 divisors (see below), whose sum is σ = 213564460032. Its totient is φ = 73261393920.
The previous prime is 134110412999. The next prime is 134110413011. The reversal of 134110413003 is 300314011431.
It is not a de Polignac number, because 134110413003 - 22 = 134110412999 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is not an unprimeable number, because it can be changed into a prime (134110413403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 51244551 + ... + 51247167.
It is an arithmetic number, because the mean of its divisors is an integer number (3336944688).
Almost surely, 2134110413003 is an apocalyptic number.
134110413003 is a deficient number, since it is larger than the sum of its proper divisors (79454047029).
134110413003 is a wasteful number, since it uses less digits than its factorization.
134110413003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3844.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 134110413003 its reverse (300314011431), we get a palindrome (434424424434).
The spelling of 134110413003 in words is "one hundred thirty-four billion, one hundred ten million, four hundred thirteen thousand, three".
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