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1341104434 = 2670552217
BaseRepresentation
bin100111111101111…
…1010000100110010
310110110112011102121
41033323322010302
510221310320214
6341024304454
745143125315
oct11773720462
93413464377
101341104434
1162902267a
1231517212a
13184aca427
14ca18097c
157cb0e424
hex4fefa132

1341104434 has 4 divisors (see below), whose sum is σ = 2011656654. Its totient is φ = 670552216.

The previous prime is 1341104419. The next prime is 1341104441. The reversal of 1341104434 is 4344011431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1284147225 + 56957209 = 35835^2 + 7547^2 .

It is a super-2 number, since 2×13411044342 = 3597122205788920712, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1341104399 and 1341104408.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335276107 + ... + 335276110.

Almost surely, 21341104434 is an apocalyptic number.

1341104434 is a deficient number, since it is larger than the sum of its proper divisors (670552220).

1341104434 is an equidigital number, since it uses as much as digits as its factorization.

1341104434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 670552219.

The product of its (nonzero) digits is 2304, while the sum is 25.

The square root of 1341104434 is about 36621.0927472133. The cubic root of 1341104434 is about 1102.7765762136.

Adding to 1341104434 its reverse (4344011431), we get a palindrome (5685115865).

The spelling of 1341104434 in words is "one billion, three hundred forty-one million, one hundred four thousand, four hundred thirty-four".

Divisors: 1 2 670552217 1341104434