Base | Representation |
---|---|
bin | 1100001100101000010100… |
… | …1100000010101001010011 |
3 | 1202111002110011212121012212 |
4 | 3003022011030002221103 |
5 | 3224211434320040103 |
6 | 44304552400542335 |
7 | 2552631054504614 |
oct | 303120514025123 |
9 | 52432404777185 |
10 | 13411122424403 |
11 | 4300696a88180 |
12 | 16071b99219ab |
13 | 7638816b6672 |
14 | 34515d445c0b |
15 | 183cc27537d8 |
hex | c3285302a53 |
13411122424403 has 16 divisors (see below), whose sum is σ = 14833957248000. Its totient is φ = 12023312273280.
The previous prime is 13411122424361. The next prime is 13411122424433. The reversal of 13411122424403 is 30442422111431.
It is not a de Polignac number, because 13411122424403 - 212 = 13411122420307 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13411122424403.
It is not an unprimeable number, because it can be changed into a prime (13411122424433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26861483 + ... + 27356196.
It is an arithmetic number, because the mean of its divisors is an integer number (927122328000).
Almost surely, 213411122424403 is an apocalyptic number.
13411122424403 is a deficient number, since it is larger than the sum of its proper divisors (1422834823597).
13411122424403 is a wasteful number, since it uses less digits than its factorization.
13411122424403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54218002.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 13411122424403 its reverse (30442422111431), we get a palindrome (43853544535834).
The spelling of 13411122424403 in words is "thirteen trillion, four hundred eleven billion, one hundred twenty-two million, four hundred twenty-four thousand, four hundred three".
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