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134112101424331 is a prime number
BaseRepresentation
bin11110011111100101101000…
…001010100101110011001011
3122120211222202221022101022211
4132133211220022211303023
5120034243040431034311
61153122125430325551
740151164616123602
oct3637455012456313
9576758687271284
10134112101424331
1139806693a60128
121305b9a74b98b7
1359aa942046a64
1425190bb81ca39
15107886bd95821
hex79f9682a5ccb

134112101424331 has 2 divisors, whose sum is σ = 134112101424332. Its totient is φ = 134112101424330.

The previous prime is 134112101424311. The next prime is 134112101424349. The reversal of 134112101424331 is 133424101211431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134112101424331 - 215 = 134112101391563 is a prime.

It is a super-2 number, since 2×1341121014243312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134112101424293 and 134112101424302.

It is not a weakly prime, because it can be changed into another prime (134112101424311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67056050712165 + 67056050712166.

It is an arithmetic number, because the mean of its divisors is an integer number (67056050712166).

Almost surely, 2134112101424331 is an apocalyptic number.

134112101424331 is a deficient number, since it is larger than the sum of its proper divisors (1).

134112101424331 is an equidigital number, since it uses as much as digits as its factorization.

134112101424331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 134112101424331 its reverse (133424101211431), we get a palindrome (267536202635762).

The spelling of 134112101424331 in words is "one hundred thirty-four trillion, one hundred twelve billion, one hundred one million, four hundred twenty-four thousand, three hundred thirty-one".