134112312043533 has 10 divisors (see below), whose sum is σ = 200340614287374. Its totient is φ = 89408208028968.

The previous prime is 134112312043447. The next prime is 134112312043547. The reversal of 134112312043533 is 335340213211431.

134112312043533 is a `hidden beast` number, since 1 + 3 + 4 + 112 + 3 + 1 + 2 + 0 + 4 + 3 + 533 = 666.

134112312043533 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 109962970060329 + 24149341983204 = 10486323^2 + 4914198^2 .

It is not a de Polignac number, because 134112312043533 - 2¹⁷ = 134112311912461 is a prime.

It is a super-2 number, since 2×134112312043533² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134112312043433) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 827853777966 + ... + 827853778127.

Almost surely, 2^{134112312043533} is an apocalyptic number.

It is an amenable number.

134112312043533 is a deficient number, since it is larger than the sum of its proper divisors (66228302243841).

134112312043533 is an equidigital number, since it uses as much as digits as its factorization.

134112312043533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1655707556105 (or 1655707556096 counting only the distinct ones).

The product of its (nonzero) digits is 77760, while the sum is 36.

Adding to 134112312043533 its reverse (335340213211431), we get a palindrome (469452525254964).

The spelling of 134112312043533 in words is "one hundred thirty-four trillion, one hundred twelve billion, three hundred twelve million, forty-three thousand, five hundred thirty-three".