Base | Representation |
---|---|
bin | 11000111110110000… |
… | …01001000011010010 |
3 | 1021121122202212001221 |
4 | 30133120021003102 |
5 | 204431244332424 |
6 | 10054443115254 |
7 | 653226242206 |
oct | 143730110322 |
9 | 37548685057 |
10 | 13411324114 |
11 | 5762385341 |
12 | 2723512b2a |
13 | 1359679756 |
14 | 91323ab06 |
15 | 5376009e4 |
hex | 31f6090d2 |
13411324114 has 4 divisors (see below), whose sum is σ = 20116986174. Its totient is φ = 6705662056.
The previous prime is 13411324111. The next prime is 13411324117. The reversal of 13411324114 is 41142311431.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (13411324111) and next prime (13411324117).
It can be written as a sum of positive squares in only one way, i.e., 13125139225 + 286184889 = 114565^2 + 16917^2 .
It is a super-2 number, since 2×134113241142 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13411324111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3352831027 + ... + 3352831030.
Almost surely, 213411324114 is an apocalyptic number.
13411324114 is a deficient number, since it is larger than the sum of its proper divisors (6705662060).
13411324114 is an equidigital number, since it uses as much as digits as its factorization.
13411324114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6705662059.
The product of its digits is 1152, while the sum is 25.
Adding to 13411324114 its reverse (41142311431), we get a palindrome (54553635545).
The spelling of 13411324114 in words is "thirteen billion, four hundred eleven million, three hundred twenty-four thousand, one hundred fourteen".
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