13411324130 has 8 divisors (see below), whose sum is σ = 24140383452. Its totient is φ = 5364529648.

The previous prime is 13411324117. The next prime is 13411324159. The reversal of 13411324130 is 3142311431.

It can be written as a sum of positive squares in 2 ways, for example, as 12706474729 + 704849401 = 112723^2 + 26549^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13411324130² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13411324096 and 13411324105.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 670566197 + ... + 670566216.

Almost surely, 2^13411324130 is an apocalyptic number.

13411324130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13411324130 is a deficient number, since it is larger than the sum of its proper divisors (10729059322).

13411324130 is a wasteful number, since it uses less digits than its factorization.

13411324130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1341132420.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 13411324130 its reverse (3142311431), we get a palindrome (16553635561).

The spelling of 13411324130 in words is "thirteen billion, four hundred eleven million, three hundred twenty-four thousand, one hundred thirty".