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134113255320001 is a prime number
BaseRepresentation
bin11110011111100110101100…
…111100010110100111000001
3122120212002202100120100121111
4132133212230330112213001
5120034302421330220001
61153122440130323321
740151235330101116
oct3637465474264701
9576762670510544
10134113255320001
1139807126337011
1213060069a29541
1359aaa97118069
14251918ab8a90d
1510788d8325851
hex79f9acf169c1

134113255320001 has 2 divisors, whose sum is σ = 134113255320002. Its totient is φ = 134113255320000.

The previous prime is 134113255319993. The next prime is 134113255320043. The reversal of 134113255320001 is 100023552311431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 79393873784976 + 54719381535025 = 8910324^2 + 7397255^2 .

It is a cyclic number.

It is not a de Polignac number, because 134113255320001 - 23 = 134113255319993 is a prime.

It is not a weakly prime, because it can be changed into another prime (134113255320101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67056627660000 + 67056627660001.

It is an arithmetic number, because the mean of its divisors is an integer number (67056627660001).

Almost surely, 2134113255320001 is an apocalyptic number.

It is an amenable number.

134113255320001 is a deficient number, since it is larger than the sum of its proper divisors (1).

134113255320001 is an equidigital number, since it uses as much as digits as its factorization.

134113255320001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 31.

The spelling of 134113255320001 in words is "one hundred thirty-four trillion, one hundred thirteen billion, two hundred fifty-five million, three hundred twenty thousand, one".