134113433 has 2 divisors, whose sum is σ = 134113434. Its totient is φ = 134113432.

The previous prime is 134113411. The next prime is 134113439. The reversal of 134113433 is 334311431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105842944 + 28270489 = 10288^2 + 5317^2 .

It is a cyclic number.

It is not a de Polignac number, because 134113433 - 2²⁰ = 133064857 is a prime.

It is a super-2 number, since 2×134113433² = 35972825822090978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134113399 and 134113408.

It is not a weakly prime, because it can be changed into another prime (134113439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67056716 + 67056717.

It is an arithmetic number, because the mean of its divisors is an integer number (67056717).

Almost surely, 2^134113433 is an apocalyptic number.

It is an amenable number.

134113433 is a deficient number, since it is larger than the sum of its proper divisors (1).

134113433 is an equidigital number, since it uses as much as digits as its factorization.

134113433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1296, while the sum is 23.

The square root of 134113433 is about 11580.7354256973. The cubic root of 134113433 is about 511.8673476841.

Adding to 134113433 its reverse (334311431), we get a palindrome (468424864).

The spelling of 134113433 in words is "one hundred thirty-four million, one hundred thirteen thousand, four hundred thirty-three".