Base | Representation |
---|---|
bin | 11110011111100111011011… |
… | …111001101010110101001111 |
3 | 122120212011210021000001002120 |
4 | 132133213123321222311033 |
5 | 120034311030021124201 |
6 | 1153123050232224023 |
7 | 40151264004360450 |
oct | 3637473371526517 |
9 | 576764707001076 |
10 | 134114043145551 |
11 | 398074a0012007 |
12 | 1306024983b013 |
13 | 59aab913c7721 |
14 | 2519223667127 |
15 | 1078932595536 |
hex | 79f9dbe6ad4f |
134114043145551 has 32 divisors (see below), whose sum is σ = 217837936051200. Its totient is φ = 71644476688896.
The previous prime is 134114043145547. The next prime is 134114043145553. The reversal of 134114043145551 is 155541340411431.
It is not a de Polignac number, because 134114043145551 - 22 = 134114043145547 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134114043145553) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1260583011 + ... + 1260689396.
It is an arithmetic number, because the mean of its divisors is an integer number (6807435501600).
Almost surely, 2134114043145551 is an apocalyptic number.
134114043145551 is a deficient number, since it is larger than the sum of its proper divisors (83723892905649).
134114043145551 is a wasteful number, since it uses less digits than its factorization.
134114043145551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2521272583.
The product of its (nonzero) digits is 288000, while the sum is 42.
Adding to 134114043145551 its reverse (155541340411431), we get a palindrome (289655383556982).
The spelling of 134114043145551 in words is "one hundred thirty-four trillion, one hundred fourteen billion, forty-three million, one hundred forty-five thousand, five hundred fifty-one".
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