Base | Representation |
---|---|
bin | 1100001100101001011100… |
… | …0111111100011110100011 |
3 | 1202111010020011002201102200 |
4 | 3003022113013330132203 |
5 | 3224213043333343301 |
6 | 44305042310344243 |
7 | 2552641400321103 |
oct | 303122707743643 |
9 | 52433204081380 |
10 | 13411423340451 |
11 | 4300830927924 |
12 | 160728265b083 |
13 | 7638cbb453b6 |
14 | 34518b3b7203 |
15 | 183cddd93c86 |
hex | c32971fc7a3 |
13411423340451 has 24 divisors (see below), whose sum is σ = 19822913510400. Its totient is φ = 8732868013296.
The previous prime is 13411423340443. The next prime is 13411423340453. The reversal of 13411423340451 is 15404332411431.
13411423340451 is a `hidden beast` number, since 1 + 3 + 4 + 1 + 14 + 233 + 404 + 5 + 1 = 666.
It is not a de Polignac number, because 13411423340451 - 23 = 13411423340443 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13411423340453) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 24653350 + ... + 25191476.
It is an arithmetic number, because the mean of its divisors is an integer number (825954729600).
Almost surely, 213411423340451 is an apocalyptic number.
13411423340451 is a deficient number, since it is larger than the sum of its proper divisors (6411490169949).
13411423340451 is a wasteful number, since it uses less digits than its factorization.
13411423340451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 602575 (or 602572 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 36.
Adding to 13411423340451 its reverse (15404332411431), we get a palindrome (28815755751882).
The spelling of 13411423340451 in words is "thirteen trillion, four hundred eleven billion, four hundred twenty-three million, three hundred forty thousand, four hundred fifty-one".
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