Base | Representation |
---|---|
bin | 10011100001000010010… |
… | …100010000010100011011 |
3 | 11202012201112001001010002 |
4 | 103201002110100110123 |
5 | 133433124423333311 |
6 | 2504040132043215 |
7 | 165615521220254 |
oct | 23410224202433 |
9 | 4665645031102 |
10 | 1341142402331 |
11 | 477858a16a96 |
12 | 197b09a6350b |
13 | 99613a557c4 |
14 | 48ca9771b2b |
15 | 24d45d6b93b |
hex | 1384251051b |
1341142402331 has 2 divisors, whose sum is σ = 1341142402332. Its totient is φ = 1341142402330.
The previous prime is 1341142402321. The next prime is 1341142402387. The reversal of 1341142402331 is 1332042411431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1341142402331 - 230 = 1340068660507 is a prime.
It is a super-2 number, since 2×13411424023312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 1341142402294 and 1341142402303.
It is not a weakly prime, because it can be changed into another prime (1341142402321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670571201165 + 670571201166.
It is an arithmetic number, because the mean of its divisors is an integer number (670571201166).
Almost surely, 21341142402331 is an apocalyptic number.
1341142402331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341142402331 is an equidigital number, since it uses as much as digits as its factorization.
1341142402331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1341142402331 its reverse (1332042411431), we get a palindrome (2673184813762).
The spelling of 1341142402331 in words is "one trillion, three hundred forty-one billion, one hundred forty-two million, four hundred two thousand, three hundred thirty-one".
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