1341144434031 has 4 divisors (see below), whose sum is σ = 1788192578712. Its totient is φ = 894096289352.

The previous prime is 1341144434011. The next prime is 1341144434051. The reversal of 1341144434031 is 1304344411431.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1341144434011) and next prime (1341144434051).

It is a cyclic number.

It is not a de Polignac number, because 1341144434031 - 2⁵ = 1341144433999 is a prime.

It is a super-2 number, since 2×1341144434031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1341144433983 and 1341144434001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341144434011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223524072336 + ... + 223524072341.

It is an arithmetic number, because the mean of its divisors is an integer number (447048144678).

Almost surely, 2^{1341144434031} is an apocalyptic number.

1341144434031 is a deficient number, since it is larger than the sum of its proper divisors (447048144681).

1341144434031 is an equidigital number, since it uses as much as digits as its factorization.

1341144434031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 447048144680.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 1341144434031 its reverse (1304344411431), we get a palindrome (2645488845462).

The spelling of 1341144434031 in words is "one trillion, three hundred forty-one billion, one hundred forty-four million, four hundred thirty-four thousand, thirty-one".