Base | Representation |
---|---|
bin | 10011100001000010011… |
… | …100000000010110000011 |
3 | 11202012201122212021002222 |
4 | 103201002130000112003 |
5 | 133433130433342201 |
6 | 2504040243401255 |
7 | 165615544411532 |
oct | 23410234002603 |
9 | 4665648767088 |
10 | 1341144434051 |
11 | 47785a0844a4 |
12 | 197b0a68322b |
13 | 996142b74c6 |
14 | 48ca9b40319 |
15 | 24d4611d91b |
hex | 13842700583 |
1341144434051 has 2 divisors, whose sum is σ = 1341144434052. Its totient is φ = 1341144434050.
The previous prime is 1341144434011. The next prime is 1341144434053. The reversal of 1341144434051 is 1504344411431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1341144434051 - 238 = 1066266527107 is a prime.
Together with 1341144434053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1341144434053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670572217025 + 670572217026.
It is an arithmetic number, because the mean of its divisors is an integer number (670572217026).
Almost surely, 21341144434051 is an apocalyptic number.
1341144434051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341144434051 is an equidigital number, since it uses as much as digits as its factorization.
1341144434051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 1341144434051 its reverse (1504344411431), we get a palindrome (2845488845482).
The spelling of 1341144434051 in words is "one trillion, three hundred forty-one billion, one hundred forty-four million, four hundred thirty-four thousand, fifty-one".
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