13411534150343 has 4 divisors (see below), whose sum is σ = 15327467600400. Its totient is φ = 11495600700288.

The previous prime is 13411534150297. The next prime is 13411534150369. The reversal of 13411534150343 is 34305143511431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13411534150343 - 2²² = 13411529956039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13411534150297 and 13411534150306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13411534150243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 957966725018 + ... + 957966725031.

It is an arithmetic number, because the mean of its divisors is an integer number (3831866900100).

Almost surely, 2^{13411534150343} is an apocalyptic number.

13411534150343 is a deficient number, since it is larger than the sum of its proper divisors (1915933450057).

13411534150343 is an equidigital number, since it uses as much as digits as its factorization.

13411534150343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1915933450056.

The product of its (nonzero) digits is 129600, while the sum is 38.

Adding to 13411534150343 its reverse (34305143511431), we get a palindrome (47716677661774).

The spelling of 13411534150343 in words is "thirteen trillion, four hundred eleven billion, five hundred thirty-four million, one hundred fifty thousand, three hundred forty-three".