Base | Representation |
---|---|
bin | 1100001100101001110111… |
… | …0000001011010101100011 |
3 | 1202111010111220100202202121 |
4 | 3003022131300023111203 |
5 | 3224213310321102441 |
6 | 44305101322125111 |
7 | 2552644220512216 |
oct | 303123560132543 |
9 | 52433456322677 |
10 | 13411534550371 |
11 | 4300888685551 |
12 | 16072b3950797 |
13 | 763918bb2399 |
14 | 34519c08577d |
15 | 183ce8a0edd1 |
hex | c329dc0b563 |
13411534550371 has 2 divisors, whose sum is σ = 13411534550372. Its totient is φ = 13411534550370.
The previous prime is 13411534550341. The next prime is 13411534550383. The reversal of 13411534550371 is 17305543511431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13411534550371 - 231 = 13409387066723 is a prime.
It is a super-2 number, since 2×134115345503712 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13411534550341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705767275185 + 6705767275186.
It is an arithmetic number, because the mean of its divisors is an integer number (6705767275186).
Almost surely, 213411534550371 is an apocalyptic number.
13411534550371 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411534550371 is an equidigital number, since it uses as much as digits as its factorization.
13411534550371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 378000, while the sum is 43.
The spelling of 13411534550371 in words is "thirteen trillion, four hundred eleven billion, five hundred thirty-four million, five hundred fifty thousand, three hundred seventy-one".
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