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1341200313311 = 1381971180531
BaseRepresentation
bin10011100001000101110…
…001001010101111011111
311202012212120000020001012
4103201011301022233133
5133433234240011221
62504050001205435
7165620123364035
oct23410561125737
94665776006035
101341200313311
11477888680401
12197b2533087b
1399622a50961
1448cb3328555
1524d4aeaa65b
hex13845c4abdf

1341200313311 has 4 divisors (see below), whose sum is σ = 1342171495224. Its totient is φ = 1340229131400.

The previous prime is 1341200313301. The next prime is 1341200313391. The reversal of 1341200313311 is 1133130021431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1341200313311 - 214 = 1341200296927 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341200313301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 485588885 + ... + 485591646.

It is an arithmetic number, because the mean of its divisors is an integer number (335542873806).

Almost surely, 21341200313311 is an apocalyptic number.

1341200313311 is a deficient number, since it is larger than the sum of its proper divisors (971181913).

1341200313311 is an equidigital number, since it uses as much as digits as its factorization.

1341200313311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 971181912.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1341200313311 its reverse (1133130021431), we get a palindrome (2474330334742).

The spelling of 1341200313311 in words is "one trillion, three hundred forty-one billion, two hundred million, three hundred thirteen thousand, three hundred eleven".

Divisors: 1 1381 971180531 1341200313311