Base | Representation |
---|---|
bin | 10011100001000101110… |
… | …001001010110000101111 |
3 | 11202012212120000020011011 |
4 | 103201011301022300233 |
5 | 133433234240012031 |
6 | 2504050001210051 |
7 | 165620123364211 |
oct | 23410561126057 |
9 | 4665776006134 |
10 | 1341200313391 |
11 | 477888680474 |
12 | 197b25330927 |
13 | 99622a509c3 |
14 | 48cb33285b1 |
15 | 24d4aeaa6b1 |
hex | 13845c4ac2f |
1341200313391 has 2 divisors, whose sum is σ = 1341200313392. Its totient is φ = 1341200313390.
The previous prime is 1341200313301. The next prime is 1341200313413. The reversal of 1341200313391 is 1933130021431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1341200313391 - 213 = 1341200305199 is a prime.
It is a super-2 number, since 2×13412003133912 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1341200313301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670600156695 + 670600156696.
It is an arithmetic number, because the mean of its divisors is an integer number (670600156696).
Almost surely, 21341200313391 is an apocalyptic number.
1341200313391 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341200313391 is an equidigital number, since it uses as much as digits as its factorization.
1341200313391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 31.
The spelling of 1341200313391 in words is "one trillion, three hundred forty-one billion, two hundred million, three hundred thirteen thousand, three hundred ninety-one".
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