1341200314042 has 4 divisors (see below), whose sum is σ = 2011800471066. Its totient is φ = 670600157020.

The previous prime is 1341200314037. The next prime is 1341200314049. The reversal of 1341200314042 is 2404130021431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 738948263641 + 602252050401 = 859621^2 + 776049^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1341200313998 and 1341200314016.

It is not an unprimeable number, because it can be changed into a prime (1341200314049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335300078509 + ... + 335300078512.

Almost surely, 2^{1341200314042} is an apocalyptic number.

1341200314042 is a deficient number, since it is larger than the sum of its proper divisors (670600157024).

1341200314042 is an equidigital number, since it uses as much as digits as its factorization.

1341200314042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 670600157023.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1341200314042 its reverse (2404130021431), we get a palindrome (3745330335473).

The spelling of 1341200314042 in words is "one trillion, three hundred forty-one billion, two hundred million, three hundred fourteen thousand, forty-two".