Base | Representation |
---|---|
bin | 11110011111101101000110… |
… | …110110011101100011000010 |
3 | 122120212202111122001221122121 |
4 | 132133231012312131203002 |
5 | 120034411012400342424 |
6 | 1153125534354554454 |
7 | 40151600624436361 |
oct | 3637550666354302 |
9 | 576782448057577 |
10 | 134120132434114 |
11 | 3980a0352886a2 |
12 | 13061468b98a2a |
13 | 59ab621b26658 |
14 | 25196402797d8 |
15 | 1078b8be68ee4 |
hex | 79fb46d9d8c2 |
134120132434114 has 4 divisors (see below), whose sum is σ = 201180198651174. Its totient is φ = 67060066217056.
The previous prime is 134120132434097. The next prime is 134120132434139. The reversal of 134120132434114 is 411434231021431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 83620874358025 + 50499258076089 = 9144445^2 + 7106283^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 134120132434114.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33530033108527 + ... + 33530033108530.
Almost surely, 2134120132434114 is an apocalyptic number.
134120132434114 is a deficient number, since it is larger than the sum of its proper divisors (67060066217060).
134120132434114 is an equidigital number, since it uses as much as digits as its factorization.
134120132434114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67060066217059.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 134120132434114 its reverse (411434231021431), we get a palindrome (545554363455545).
The spelling of 134120132434114 in words is "one hundred thirty-four trillion, one hundred twenty billion, one hundred thirty-two million, four hundred thirty-four thousand, one hundred fourteen".
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