Base | Representation |
---|---|
bin | 1100001100101011101001… |
… | …0011001111000000100110 |
3 | 1202111011202021121001120102 |
4 | 3003022322103033000212 |
5 | 3224220300424040002 |
6 | 44305221031504102 |
7 | 2552662124524136 |
oct | 303127223170046 |
9 | 52434667531512 |
10 | 13412013502502 |
11 | 4301003a7635a |
12 | 1607408228032 |
13 | 7639941a8104 |
14 | 34520591cac6 |
15 | 183d25abba02 |
hex | c32ba4cf026 |
13412013502502 has 4 divisors (see below), whose sum is σ = 20118020253756. Its totient is φ = 6706006751250.
The previous prime is 13412013502483. The next prime is 13412013502507. The reversal of 13412013502502 is 20520531021431.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13412013502507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3353003375624 + ... + 3353003375627.
It is an arithmetic number, because the mean of its divisors is an integer number (5029505063439).
Almost surely, 213412013502502 is an apocalyptic number.
13412013502502 is a deficient number, since it is larger than the sum of its proper divisors (6706006751254).
13412013502502 is an equidigital number, since it uses as much as digits as its factorization.
13412013502502 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6706006751253.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 13412013502502 its reverse (20520531021431), we get a palindrome (33932544523933).
The spelling of 13412013502502 in words is "thirteen trillion, four hundred twelve billion, thirteen million, five hundred two thousand, five hundred two".
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