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1341204340032 = 2635487717683
BaseRepresentation
bin10011100001000110000…
…000100001110101000000
311202012212211120210200000
4103201012000201311000
5133433241302340112
62504050223400000
7165620202534534
oct23410600416500
94665784523600
101341204340032
1147788a980777
12197b26753000
139962383072b
1448cb3a95bc4
1524d4b5037dc
hex13846021d40

1341204340032 has 168 divisors, whose sum is σ = 3987745253856. Its totient is φ = 446951167488.

The previous prime is 1341204340009. The next prime is 1341204340087. The reversal of 1341204340032 is 2300434021431.

1341204340032 is a `hidden beast` number, since 13 + 41 + 204 + 3 + 400 + 3 + 2 = 666.

It is a super-2 number, since 2×13412043400322 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 1341204339978 and 1341204340005.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 75838263 + ... + 75855945.

It is an arithmetic number, because the mean of its divisors is an integer number (23736578892).

Almost surely, 21341204340032 is an apocalyptic number.

1341204340032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1341204340032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1993872626928).

1341204340032 is an abundant number, since it is smaller than the sum of its proper divisors (2646540913824).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1341204340032 is an equidigital number, since it uses as much as digits as its factorization.

1341204340032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22587 (or 22565 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 1341204340032 its reverse (2300434021431), we get a palindrome (3641638361463).

The spelling of 1341204340032 in words is "one trillion, three hundred forty-one billion, two hundred four million, three hundred forty thousand, thirty-two".