Base | Representation |
---|---|
bin | 1100001100101011111101… |
… | …1101110001110011100001 |
3 | 1202111011222022122100002021 |
4 | 3003022333131301303201 |
5 | 3224220440114340140 |
6 | 44305233405021441 |
7 | 2552664226165153 |
oct | 303127735616341 |
9 | 52434868570067 |
10 | 13412100152545 |
11 | 4301048979866 |
12 | 1607431254881 |
13 | 7639a9126323 |
14 | 345213236ad3 |
15 | 183d2d4d5b4a |
hex | c32bf771ce1 |
13412100152545 has 32 divisors (see below), whose sum is σ = 16249621973760. Its totient is φ = 10626672380160.
The previous prime is 13412100152537. The next prime is 13412100152579. The reversal of 13412100152545 is 54525100121431.
It is not a de Polignac number, because 13412100152545 - 23 = 13412100152537 is a prime.
It is a super-2 number, since 2×134121001525452 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13412100152545.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 958205487 + ... + 958219483.
It is an arithmetic number, because the mean of its divisors is an integer number (507800686680).
Almost surely, 213412100152545 is an apocalyptic number.
It is an amenable number.
13412100152545 is a deficient number, since it is larger than the sum of its proper divisors (2837521821215).
13412100152545 is a wasteful number, since it uses less digits than its factorization.
13412100152545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17385.
The product of its (nonzero) digits is 24000, while the sum is 34.
Adding to 13412100152545 its reverse (54525100121431), we get a palindrome (67937200273976).
The spelling of 13412100152545 in words is "thirteen trillion, four hundred twelve billion, one hundred million, one hundred fifty-two thousand, five hundred forty-five".
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