Base | Representation |
---|---|
bin | 111110011101000111… |
… | …1011100001101100111 |
3 | 110211012010112110002021 |
4 | 1330322033130031213 |
5 | 4144140001044143 |
6 | 141340412524011 |
7 | 12455434434244 |
oct | 1747217341547 |
9 | 424163473067 |
10 | 134121112423 |
11 | 51975964971 |
12 | 21bb0a80607 |
13 | c85591c5ac |
14 | 66c49485cb |
15 | 374ea5dced |
hex | 1f3a3dc367 |
134121112423 has 4 divisors (see below), whose sum is σ = 141180118360. Its totient is φ = 127062106488.
The previous prime is 134121112381. The next prime is 134121112529. The reversal of 134121112423 is 324211121431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 324211121431 = 8597 ⋅37712123.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134121112423 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134121412423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3529502940 + ... + 3529502977.
It is an arithmetic number, because the mean of its divisors is an integer number (35295029590).
Almost surely, 2134121112423 is an apocalyptic number.
134121112423 is a deficient number, since it is larger than the sum of its proper divisors (7059005937).
134121112423 is an equidigital number, since it uses as much as digits as its factorization.
134121112423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7059005936.
The product of its digits is 1152, while the sum is 25.
Adding to 134121112423 its reverse (324211121431), we get a palindrome (458332233854).
The spelling of 134121112423 in words is "one hundred thirty-four billion, one hundred twenty-one million, one hundred twelve thousand, four hundred twenty-three".
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