Base | Representation |
---|---|
bin | 11110011111101111001111… |
… | …011001000011000101111011 |
3 | 122120212222102021120000122222 |
4 | 132133233033121003011323 |
5 | 120034430210314432141 |
6 | 1153130553550034255 |
7 | 40152011451600425 |
oct | 3637571731030573 |
9 | 576788367500588 |
10 | 134122423202171 |
11 | 39810000373638 |
12 | 130619a81a898b |
13 | 59ab8c85b8701 |
14 | 25197ba5c3815 |
15 | 1078c7311514b |
hex | 79fbcf64317b |
134122423202171 has 2 divisors, whose sum is σ = 134122423202172. Its totient is φ = 134122423202170.
The previous prime is 134122423202149. The next prime is 134122423202231. The reversal of 134122423202171 is 171202324221431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134122423202171 - 226 = 134122356093307 is a prime.
It is a super-2 number, since 2×1341224232021712 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134122423202101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67061211601085 + 67061211601086.
It is an arithmetic number, because the mean of its divisors is an integer number (67061211601086).
Almost surely, 2134122423202171 is an apocalyptic number.
134122423202171 is a deficient number, since it is larger than the sum of its proper divisors (1).
134122423202171 is an equidigital number, since it uses as much as digits as its factorization.
134122423202171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 35.
The spelling of 134122423202171 in words is "one hundred thirty-four trillion, one hundred twenty-two billion, four hundred twenty-three million, two hundred two thousand, one hundred seventy-one".
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