Base | Representation |
---|---|
bin | 1100001100101101001011… |
… | …0011000110110001000101 |
3 | 1202111012210220222102121002 |
4 | 3003023102303012301011 |
5 | 3224222121133314113 |
6 | 44305325513103045 |
7 | 2553005245164236 |
oct | 303132263066105 |
9 | 52435726872532 |
10 | 13412424510533 |
11 | 43011a4a7a814 |
12 | 16075019b7a85 |
13 | 763a2b3a2029 |
14 | 34524434b08d |
15 | 183d4bc06c58 |
hex | c32d2cc6c45 |
13412424510533 has 4 divisors (see below), whose sum is σ = 13412441135520. Its totient is φ = 13412407885548.
The previous prime is 13412424510523. The next prime is 13412424510547. The reversal of 13412424510533 is 33501542421431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13412424510533 - 214 = 13412424494149 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13412424510523) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7037123 + ... + 8737616.
It is an arithmetic number, because the mean of its divisors is an integer number (3353110283880).
Almost surely, 213412424510533 is an apocalyptic number.
It is an amenable number.
13412424510533 is a deficient number, since it is larger than the sum of its proper divisors (16624987).
13412424510533 is an equidigital number, since it uses as much as digits as its factorization.
13412424510533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16624986.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 13412424510533 its reverse (33501542421431), we get a palindrome (46913966931964).
The spelling of 13412424510533 in words is "thirteen trillion, four hundred twelve billion, four hundred twenty-four million, five hundred ten thousand, five hundred thirty-three".
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