Search a number
-
+
13412443422242 = 26706221711121
BaseRepresentation
bin1100001100101101001111…
…1011001111111000100010
31202111012212020120020120202
43003023103323033320202
53224222141004002432
644305331430305202
72553005565011354
oct303132373177042
952435766506522
1013412443422242
114301204717427
1216075081b8202
13763a32293ca7
14345246a710d4
15183d4d6e0462
hexc32d3ecfe22

13412443422242 has 4 divisors (see below), whose sum is σ = 20118665133366. Its totient is φ = 6706221711120.

The previous prime is 13412443422239. The next prime is 13412443422251. The reversal of 13412443422242 is 24222434421431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12368451968161 + 1043991454081 = 3516881^2 + 1021759^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13412443422196 and 13412443422205.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3353110855559 + ... + 3353110855562.

Almost surely, 213412443422242 is an apocalyptic number.

13412443422242 is a deficient number, since it is larger than the sum of its proper divisors (6706221711124).

13412443422242 is an equidigital number, since it uses as much as digits as its factorization.

13412443422242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6706221711123.

The product of its digits is 294912, while the sum is 38.

Adding to 13412443422242 its reverse (24222434421431), we get a palindrome (37634877843673).

The spelling of 13412443422242 in words is "thirteen trillion, four hundred twelve billion, four hundred forty-three million, four hundred twenty-two thousand, two hundred forty-two".

Divisors: 1 2 6706221711121 13412443422242