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134140234211 is a prime number
BaseRepresentation
bin111110011101101100…
…0011000100111100011
3110211020110111221020122
41330323120120213203
54144204344443321
6141342334430455
712456056115014
oct1747330304743
9424213457218
10134140234211
11519857353a5
1221bb736242b
13c859886069
1466c72c500b
1537515898ab
hex1f3b6189e3

134140234211 has 2 divisors, whose sum is σ = 134140234212. Its totient is φ = 134140234210.

The previous prime is 134140234201. The next prime is 134140234273. The reversal of 134140234211 is 112432041431.

It is a weak prime.

It is an emirp because it is prime and its reverse (112432041431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134140234211 is a prime.

It is a super-3 number, since 3×1341402342113 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (134140234201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67070117105 + 67070117106.

It is an arithmetic number, because the mean of its divisors is an integer number (67070117106).

Almost surely, 2134140234211 is an apocalyptic number.

134140234211 is a deficient number, since it is larger than the sum of its proper divisors (1).

134140234211 is an equidigital number, since it uses as much as digits as its factorization.

134140234211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 134140234211 its reverse (112432041431), we get a palindrome (246572275642).

The spelling of 134140234211 in words is "one hundred thirty-four billion, one hundred forty million, two hundred thirty-four thousand, two hundred eleven".