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13414110403121 is a prime number
BaseRepresentation
bin1100001100110011011101…
…0010010001101000110001
31202111101011102021122110022
43003030313102101220301
53224234044230344441
644310205055413225
72553065106062051
oct303146722215061
952441142248408
1013414110403121
11430198a68787a
1216078b2524215
13763c3974c2cc
143453641dd561
15183de9c2084b
hexc3337491a31

13414110403121 has 2 divisors, whose sum is σ = 13414110403122. Its totient is φ = 13414110403120.

The previous prime is 13414110403081. The next prime is 13414110403139. The reversal of 13414110403121 is 12130401141431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9976052763121 + 3438057640000 = 3158489^2 + 1854200^2 .

It is an emirp because it is prime and its reverse (12130401141431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13414110403121 is a prime.

It is not a weakly prime, because it can be changed into another prime (13414110408121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707055201560 + 6707055201561.

It is an arithmetic number, because the mean of its divisors is an integer number (6707055201561).

Almost surely, 213414110403121 is an apocalyptic number.

It is an amenable number.

13414110403121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13414110403121 is an equidigital number, since it uses as much as digits as its factorization.

13414110403121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 13414110403121 its reverse (12130401141431), we get a palindrome (25544511544552).

The spelling of 13414110403121 in words is "thirteen trillion, four hundred fourteen billion, one hundred ten million, four hundred three thousand, one hundred twenty-one".