13414220143 has 4 divisors (see below), whose sum is σ = 13418928088. Its totient is φ = 13409512200.

The previous prime is 13414220123. The next prime is 13414220173. The reversal of 13414220143 is 34102241431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34102241431 = 1459 ⋅23373709.

It is a cyclic number.

It is not a de Polignac number, because 13414220143 - 2⁵ = 13414220111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13414220123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2349696 + ... + 2355397.

It is an arithmetic number, because the mean of its divisors is an integer number (3354732022).

Almost surely, 2^13414220143 is an apocalyptic number.

13414220143 is a deficient number, since it is larger than the sum of its proper divisors (4707945).

13414220143 is an equidigital number, since it uses as much as digits as its factorization.

13414220143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4707944.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13414220143 its reverse (34102241431), we get a palindrome (47516461574).

The spelling of 13414220143 in words is "thirteen billion, four hundred fourteen million, two hundred twenty thousand, one hundred forty-three".