Base | Representation |
---|---|
bin | 1100001100110100001101… |
… | …1100001111101110001011 |
3 | 1202111101200122000212210112 |
4 | 3003031003130033232023 |
5 | 3224240003432441212 |
6 | 44310241222504535 |
7 | 2553103133406623 |
oct | 303150334175613 |
9 | 52441618025715 |
10 | 13414314343307 |
11 | 4301a84811089 |
12 | 160794a89514b |
13 | 763c6ca85b87 |
14 | 345383329883 |
15 | 183e0caa7422 |
hex | c334370fb8b |
13414314343307 has 2 divisors, whose sum is σ = 13414314343308. Its totient is φ = 13414314343306.
The previous prime is 13414314343291. The next prime is 13414314343333. The reversal of 13414314343307 is 70334341341431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13414314343307 - 24 = 13414314343291 is a prime.
It is not a weakly prime, because it can be changed into another prime (13414314343007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707157171653 + 6707157171654.
It is an arithmetic number, because the mean of its divisors is an integer number (6707157171654).
Almost surely, 213414314343307 is an apocalyptic number.
13414314343307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13414314343307 is an equidigital number, since it uses as much as digits as its factorization.
13414314343307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 435456, while the sum is 41.
Adding to 13414314343307 its reverse (70334341341431), we get a palindrome (83748655684738).
The spelling of 13414314343307 in words is "thirteen trillion, four hundred fourteen billion, three hundred fourteen million, three hundred forty-three thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •