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1341442102222 = 2670721051111
BaseRepresentation
bin10011100001010100001…
…011100001001111001110
311202020111101222101002001
4103201110023201033032
5133434233134232342
62504125555422514
7165626120510005
oct23412413411716
94666441871061
101341442102222
114779a2105a52
12197b922b4a3a
1399660b79b11
1448cd74a7c3c
1524d6231b8b7
hex138542e13ce

1341442102222 has 4 divisors (see below), whose sum is σ = 2012163153336. Its totient is φ = 670721051110.

The previous prime is 1341442102213. The next prime is 1341442102279. The reversal of 1341442102222 is 2222012441431.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×13414421022222 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335360525554 + ... + 335360525557.

It is an arithmetic number, because the mean of its divisors is an integer number (503040788334).

Almost surely, 21341442102222 is an apocalyptic number.

1341442102222 is a deficient number, since it is larger than the sum of its proper divisors (670721051114).

1341442102222 is an equidigital number, since it uses as much as digits as its factorization.

1341442102222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 670721051113.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 1341442102222 its reverse (2222012441431), we get a palindrome (3563454543653).

The spelling of 1341442102222 in words is "one trillion, three hundred forty-one billion, four hundred forty-two million, one hundred two thousand, two hundred twenty-two".

Divisors: 1 2 670721051111 1341442102222