Base | Representation |
---|---|
bin | 11000111111110001… |
… | …01010001010100001 |
3 | 1021122020210221010111 |
4 | 30133320222022201 |
5 | 204440440121403 |
6 | 10055345531321 |
7 | 653361554212 |
oct | 143770521241 |
9 | 37566727114 |
10 | 13419848353 |
11 | 576717776a |
12 | 2726343b41 |
13 | 135b372692 |
14 | 914419409 |
15 | 53823656d |
hex | 31fe2a2a1 |
13419848353 has 2 divisors, whose sum is σ = 13419848354. Its totient is φ = 13419848352.
The previous prime is 13419848303. The next prime is 13419848389. The reversal of 13419848353 is 35384891431.
13419848353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13230290529 + 189557824 = 115023^2 + 13768^2 .
It is a cyclic number.
It is not a de Polignac number, because 13419848353 - 233 = 4829913761 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13419848297 and 13419848306.
It is not a weakly prime, because it can be changed into another prime (13419848303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6709924176 + 6709924177.
It is an arithmetic number, because the mean of its divisors is an integer number (6709924177).
Almost surely, 213419848353 is an apocalyptic number.
It is an amenable number.
13419848353 is a deficient number, since it is larger than the sum of its proper divisors (1).
13419848353 is an equidigital number, since it uses as much as digits as its factorization.
13419848353 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1244160, while the sum is 49.
The spelling of 13419848353 in words is "thirteen billion, four hundred nineteen million, eight hundred forty-eight thousand, three hundred fifty-three".
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