Base | Representation |
---|---|
bin | 10011100001110101100… |
… | …000110110001001001011 |
3 | 11202021221101021122110111 |
4 | 103201311200312021023 |
5 | 133441404320403003 |
6 | 2504301254055151 |
7 | 165646021120531 |
oct | 23416540661113 |
9 | 4667841248414 |
10 | 1342001341003 |
11 | 478159853364 |
12 | 19810964a4b7 |
13 | 9971c9a353b |
14 | 48d4b880151 |
15 | 24d96486e6d |
hex | 1387583624b |
1342001341003 has 2 divisors, whose sum is σ = 1342001341004. Its totient is φ = 1342001341002.
The previous prime is 1342001340997. The next prime is 1342001341027. The reversal of 1342001341003 is 3001431002431.
It is a weak prime.
It is an emirp because it is prime and its reverse (3001431002431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1342001341003 - 25 = 1342001340971 is a prime.
It is not a weakly prime, because it can be changed into another prime (1342001341033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671000670501 + 671000670502.
It is an arithmetic number, because the mean of its divisors is an integer number (671000670502).
Almost surely, 21342001341003 is an apocalyptic number.
1342001341003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342001341003 is an equidigital number, since it uses as much as digits as its factorization.
1342001341003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 1342001341003 its reverse (3001431002431), we get a palindrome (4343432343434).
The spelling of 1342001341003 in words is "one trillion, three hundred forty-two billion, one million, three hundred forty-one thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •