Base | Representation |
---|---|
bin | 10011100001110110001… |
… | …111000000000000000000 |
3 | 11202021222020001100011111 |
4 | 103201312033000000000 |
5 | 133441420420040000 |
6 | 2504302405253104 |
7 | 165646226011552 |
oct | 23416617000000 |
9 | 4667866040144 |
10 | 1342013440000 |
11 | 478165667532 |
12 | 198111704194 |
13 | 9972234b5cc |
14 | 48d4d30d4d2 |
15 | 24d97576cba |
hex | 138763c0000 |
1342013440000 has 190 divisors, whose sum is σ = 3354363060224. Its totient is φ = 536739840000.
The previous prime is 1342013439989. The next prime is 1342013440013. The reversal of 1342013440000 is 443102431.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 163835905 + ... + 163844095.
Almost surely, 21342013440000 is an apocalyptic number.
1342013440000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1342013440000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1677181530112).
1342013440000 is an abundant number, since it is smaller than the sum of its proper divisors (2012349620224).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1342013440000 is an frugal number, since it uses more digits than its factorization.
1342013440000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8247 (or 8198 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 1342013440000 its reverse (443102431), we get a palindrome (1342456542431).
The spelling of 1342013440000 in words is "one trillion, three hundred forty-two billion, thirteen million, four hundred forty thousand".
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